Chem – College: Relationship Between Acid and you may Ft Equilirium Constants (Ka and you may Kb)

Chem – College: Relationship Between Acid and you may Ft Equilirium Constants (Ka and you may Kb)

When you are given multiple Ka or Kb values (like Ka step step step one , Ka dos , Ka step 3 ), you can also combine them together into an overall Ka or Kb by multiplying them together. The equations below display what I mean.

If Mg(OH) 2 has a Kb 1 of 0.3 and a Kb 2 of 4.5 * 10 -3 what is the over all Kb value?

If Become(OH)

If H 3 PO 4 has a Ka 1 of 2.8 * 10 -3 and a Ka 2 of 7.1 * 10 -6 . 3 if the overall Ka is 7.75 * 10 -17 ?

Answer: ( 2.8 * 10 -3 ) * ( 7.1 * 10 -6 ) * Ka 3 = 7.75 * 10 -17

If Al(OH) 3 has a Kb 1 of 0.04 and a Kb 2 of 5.1 * 10 -4 what is the over all Kb value?

If H 2 SO 4 has a Ka 1 of 15 and a Ka 2 of 2.0 * 10 -2 . Then what is the over all Ka value?

If H 3 PO 3 has Ka 2 of 4.7 * 10 -5 and a Ka 3 of 2.3 * 10 -8 . 1 if the overall Ka is 5.5 * 10 -16 ?

Answer: Ka1 * (4.7 * 10 -5 ) * (2.3 * 10 -8 ) = 5.5 * 10 -16 — Ka1 = 5.09 * 10 -4

2 has a Kb 1 of 3.6 * 10 -4 and an overall Kb of 8.2 * 10 -12 what would be the Kb 2 ?

Answer: (3.6 * 10 -4 ) * Kb 2 = 8.2 * 10 -12 — Kb 2 = 2.24 * 10 -8

It turns out one Ka and you may Kb was related to that some other within the an algorithm. This formula allows you to https://datingranking.net/cs/meetville-recenze/ transfer out of Ka so you’re able to Kb and you may vise versa. The newest algorithm are shown lower than .

The great thing about which algorithm could it possibly be together with allows you to assume whether or not something are an acid or a base . The way to contour if or not something try an acidic otherwise feet just by the Ka or Kb really worth is to examine it toward harmony lingering to own drinking water as in brand new equation lower than.

In the event the Ka converts planning to be a more impressive amount than just brand new Kb then the chemical substances might be an acid.

In the event your Kb turns about to be a more impressive count than just new Ka then chemical might be a bottom.

Supply the Kb and you will give whether or not the chemical substances are an acid or foot whether or not it enjoys good Ka from dos.4 * 10 -6 .

Answer: Acidic (Ka try bigger than Kb), Kb = ten -fourteen / dos.4 * 10 -6 = 4.17 * ten -nine

Provide the Ka and you will give perhaps the chemical compounds try an acidic otherwise base if this have a Kb off step 3.5 * 10 -4 .

Answer: Base (Kb was larger than Ka), Ka = ten -14 / step 3.5 * ten -cuatro = 2.86 * ten -eleven

Allow the Kb and you can give perhaps the agents try an acidic or ft whether or not it possess a beneficial Ka regarding cuatro.3 * 10 -nine .

Answer: Feet (Kb try larger than Ka), Kb = ten -14 / cuatro.step three * 10 -nine = 2.thirty two * ten -six

Provide the Ka and you can give if the chemical substances are an acid otherwise foot in the event it features an effective Kb of 8.nine * 10 -11 .

Answer: Acidic (Ka was larger than Kb), Ka = ten -fourteen / 8.9 * ten -eleven = step one.12 * 10 -cuatro

Give the Kb and you can give whether the chemicals is actually an acidic otherwise feet whether it features a great Ka out of eight.dos * 10 -9 .

Answer: Foot (Kb was bigger than Ka), Kb = ten -fourteen / seven.2 * 10 -nine = step 1.38 * ten -six

Supply the Ka and give whether the chemical compounds try an acid or feet whether or not it provides an excellent Kb away from 4.dos * 10 -a dozen .

Answer: Acidic (Ka was bigger than Kb), Ka = 10 -14 / cuatro.2 * ten -11 = 2.38 * 10 -4

Give the Kb and you will share with if the chemical is actually an acidic otherwise ft whether or not it features an effective Ka away from 3.4 * 10 -step 3 .

Next what might function as the Ka

Answer: Acidic (Ka are bigger than Kb), Kb = ten -14 / step three.4 * 10 -step 3 = 2.94 * ten -a dozen

Allow the Ka and you can give if the chemicals is an acidic otherwise foot in the event it has actually a Kb of 5.6 * 10 -seven .

Answer: Feet (Kb was bigger than Ka), Ka = 10 -fourteen / 5.six * 10 -7 = 1.78 * 10 -8